One plane leaves an hour after another plane. The first plane travels at 400mph. How fast must the second plane travel to catch up to the first plane in 2 hours

200 mph

Step-by-step explanation:

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Plane a: 400mph

Plane b: x mph

2x=400

x=200

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the second plane must travel 800 mph.

Step-by-step explanation:

Let x represent the speed of the second plane.

By the time both planes will meet, they would have covered the same distance.

Distance = speed × time

The first plane travels at 400mph.

Since the second plane caught up with the first plane in 2 hours, then the distance covered by the first plane is

400 × 2 = 800 miles

The second plane leaves an hour after the first plane. This means that the time spent by the second plane before it caught up with the first plane is 1 hour

Distance covered by the second plane is x × 1 = x

Since the distance covered is the same, then

x = 800 mph

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94

answer: what is the question you're trying to ask?

step-by-step explanation: