URGENT PLEASE HELP ME
Find the height of the lamppost to the nearest tenth (i put 110 in the box just because)

110in

Step-by-step explanation:

You are given the angle and the length of one leg of the triangle. Therefore, you will want to use one of the trigonometric formulae you've learnt. The available ones are:

where O represents the leg opposite the angle, A represents the leg Adjacent to the angle, and H represents the hypotenuse. The lamppost in this problem is the leg opposite the angle, so you want a formula that has O in the equation, namely sin or tan. Because you were given the leg adjacent to the angle, it makes sense here to use tan. Set up the equation as such to solve:

For some reason, it wanted you to convert 70 degrees to radians, so that may have been where you could have run into issues. If you plugged in 70 as degrees, you would get 48 which isn't an option. Converting 70 to 1.22 rad gets you the answer of 110 in.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.