For this right triangle, what is the cosine of angle C?
A)
12
13
B)
13
12
C)
5
12
D)
5
13
E)
13
5

A

Step-by-step explanation:

In this triangle hypotenuse=13

And perp=5

Now

Finding base

Hypotenuse^2=base^2+perp^2

(13)^2=base^2+(5)^2

169=base^2+25

Base^2=169-25

Base^2=144

Taking sq root on both sides

Base=12

Now

Cosine C=base/hypotenuse

Cosine C=12/13

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

step-by-step explanation:

the answer is 128