2. What is the factored form of x2 + 6x + 8? (1 point)
(x + 5)(x+3)
(x+4)(x+2)
(x + 7)(x + 1)
(x + 3)(x + 3)

( x + 4 ) ( x + 2 )

Step-by-step explanation:

There are two ways two approach it.

The first one is:

The other way is by finding the roots through the quadratic formula, and then factoring out. In other words:

x^2 + 6x + 8 = 0

a = 1

b = 6

c = 8

∆ = b^2 - 4ac = 4

x = ( -b +- √∆ ) / 2a

x = - 4. or x = -2

then, when p,q are the two roots of

ax^2 + bx +c =0, it can be factored out like this:

a ( x - p ) ( x - q )

1 ( x - ( -4 ) ) ( x - ( -2 ) ) = ( x + 4 ) ( x + 2 )

its a little blurry tbh

step-by-step explanation: