What is the probability that the first die will have ""a natural number greater than 1 which can only be divisible by 1 and itself""? (4 points)

The probability that the first die will have ""a natural number greater than 1 which can only be divisible by 1 and itself = 0.5

Step-by-step explanation:

A die has 6 faces with the following sample spaces 1, 2, 3, 4, 5 and 6

Then, a natural number greater than 1 which can only be divisible by 1 and itself is the definition of a prime number.

The prime numbers in the sample space are 2, 3 and 5

So, probability of getting a prime number in the sample space, P(prime numbers) = n(prime numbers)/[n(sample space)] = 3/6 = 1/2 = 0.5

17 1/3

step-by-step explanation:

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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