h(x) = -7(x – 6)^2 + 17
Mathematics, 21.02.2020 00:25 yesimabadbih5147
(8.) Rewrite the function from vertex form to standard form.
h(x) = -7(x – 6)^2 + 17
can someone give me the answer to that??
Answers: 2
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(8.) Rewrite the function from vertex form to standard form.
h(x) = -7(x – 6)^2 + 17
h(x) = -7(x – 6)^2 + 17
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