Find the probability a shopper, selected at random, spends less than 96 minutes at the mall. Show your work. The correct probability statement is required to get full credit. Write your final answer to 4 decimal places.

The probability a shopper, selected at random, spends less than 96 minutes at the mall is 0.9450

Step-by-step explanation:

Mean = xbar = 88 mins

Standard deviation = σ = 5 mins

To determine the probability the probability a shopper, selected at random, spends less than 96 minutes at the mall, we need to standardize 96 mins, that is, obtain its z-score.

The standardized score is the value minus the mean then divided by the standard deviation.

z = (x - xbar)/σ = (96 - 88)/5 = 1.6

To determine the probability the probability a shopper, selected at random, spends less than 96 minutes at the mall, P(x < 96) = P(z < 1.6)

We'll use data from the normal probability table for these probabilities

P(x < 96) = P(z < 1.6) = 1 - P(z ≥ 1.6) = 1 - P(z ≤ -1.6) = 1 - 0.055 = 0.9450

The probability a shopper, selected at random, spends less than 96 minutes at the mall is 0.9450

the correct answer is 5 6 and 7

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.