Exercise 6.13 presents the results of a poll evaluating support for the health care public option in 2009, reporting that 52% of Independents in the sample opposed the public option. If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?

A sample size of 6755 or higher would be appropriate.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

The margin of error M is given by:

90% confidence level

So , z is the value of Z that has a pvalue of , so .

52% of Independents in the sample opposed the public option.

This means that

If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?

Sample size of size n or higher when . So

A sample size of 6755 or higher would be appropriate.

y=mx+b

step-by-step explanation:

m slope

b y-intercept