For a camping trip, three scoutmasters are each driving a portion of the 150 miles to campground mr. Jimenez drives 3/10 of the distance mr robertson drives 2/5 of the distance how many miles are left for mr. Weatherly you drive

45 miles

Step-by-step explanation:

Jimenez drives 3/10 of the distance:  (3/10)(150 miles) = 45 miles.

Mr. Robertson drives 2/5 of the distance:  (2/5)(150) = 60 miles.

These two people drive 105 miles total.

Mr. Weatherly drives the rest:  (150 miles - 105 miles) = 45 miles.

your answer is a

step-by-step explanation:

4*4*4*4=256