The quadrilateral JKLM is shown below.
TUTTI ILLU11
TAI1.1 III
111
- 75
NG TUNALUL
NULLA
If this quadrilateral is reflected over the
X-axis, what rule was followed for the
new vertices?
x
B
E
(x, y) → (x,-Y)
(x, y) + (-x, y)
x, y) →. (X, Y)
(x, y) → (-X, -Y)

idk do it yourself or ask somebody idk stop going online asking for

b) well because you get well

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15