As we discussed in lecture, in order to use Z-scores to calculate proportions and probabilities, we must know that the data is disributed normally (or at least is close to normal).
A) Why is normality relevant to the calculation of proportions using Z-scores?
B) What would happen if our data was very "not normal"?
C) What use are Z-scores with "not normal" data?

Step-by-step explanation:

Introduction : Z scores are used to compute probabilities. for example if X is a norally ditributed variable and we want to know that robability of x being less than or greater tha a certain real no, say a, then we compute the z score for. and probability of ' x being less than a' is equal to probability of 'a standard normal variable being less than the z score of a '.

a) The above statement that : "probability of ' x being less than a' is equal to probability of 'a standard normal variable being less than the z score of a '. " is true because the z transformation on X gives us a standard normal variable. had X not been normal the z transformation would not follow standard normal exactly.

b) then , the probabilities will lead to wrong conclusion. because the probability based on z score is calculated from the standard normal PDF. but id the real PDF is not standard normal then calculating probabilities from z score using standard normal PDF will give erroneous answers.

c) z score for non normal data : z scores for non normal data can standardize a variable. it's like : if there is a data where the observations are all big numbers, the we calculate the z score for them. then calculate median, mode, GM etc. then we do the reverse transformation and get the actual median , mode etc.

Step-by-step explanation:

Introduction : Z scores are used to compute probabilities. for example if X is a norally ditributed variable and we want to know that robability of x being less than or greater tha a certain real no, say a, then we compute the z score for. and probability of ' x being less than a' is equal to probability of 'a standard normal variable being less than the z score of a '.

a) The above statement that : "probability of ' x being less than a' is equal to probability of 'a standard normal variable being less than the z score of a '. " is true because the z transformation on X gives us a standard normal variable. had X not been normal the z transformation would not follow standard normal exactly.

b) then , the probabilities will lead to wrong conclusion. because the probability based on z score is calculated from the standard normal PDF. but id the real PDF is not standard normal then calculating probabilities from z score using standard normal PDF will give erroneous answers.

c) z score for non normal data : z scores for non normal data can standardize a variable. it's like : if there is a data where the observations are all big numbers, the we calculate the z score for them. then calculate median, mode, GM etc. then we do the reverse transformation and get the actual median , mode etc.

Step-by-step explanation:

answer: it's upside down and i can't read it

step-by-step explanation:

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.