If 9 ≥ 4 x + 1 9≥4x+19, is greater than or equal to, 4, x, plus, 1, which inequality represents the possible range of values of 12 x + 3 12x+312, x, plus, 3?

Pssible range of values = [-∞, 27]

Step-by-step explanation:

9 ≥ 4x + 1

9 - 1 ≥ 4x ⇒ 8 ≥ 4x

Divide both sides by 4

(8/4) ≥ (4x/4) ⇒ 2 ≥ x

So, x ≤ 2

For 12x + 3, we have

12(≤2) + 3 = ≤24 + 3

= ≤27

Pssible range of values is thus [-∞, 27]

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step-by-step explanation:

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