Suppose that only 25% of all drivers come to a complete stop at an intersection having flashing red lights in all directions when no other cars are visible. What is the probability that, of 20 ran- domly chosen drivers coming to an intersection under these conditions, a. At most 6 will come to a complete stop

The probability that at most 6 will come to a complete stop is 0.7857.

Step-by-step explanation:

Let X = number of drivers come to a complete stop at an intersection having flashing red lights in all directions when no other cars are visible.

The probability of the event X is, P (X) = p = 0.25.

The sample of drivers randomly selected is of size, n = 20.

The random variable X follows a binomial distribution with parameters n = 6 and p = 0.25.

The probability function of  Binomial distribution is:

Compute the probability that at most 6 will come to a complete stop as follows:

P (X ≤ 6) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3)

                     + P (X = 4) + P (X = 5) + P (X = 6)

Thus, the probability that at most 6 will come to a complete stop is 0.7857.

its definatley   this on your answer choice?

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.