What is the surface area of the pyramid formed from the net shown here? The triangles are equilateral, and each triangle has a height of 5.2 centimeters.

62.4 square centimeters

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The surface area of the triangular pyramid is equal to the area of the triangular base plus the area of its three lateral triangular faces

In this problem the triangles are equilateral, that means, the

surface area is equal to the area of four congruent equilateral triangles

so

we have

substitute

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

sorry man i accidentally pressed yes my bad

step-by-step explanation: