What error did the student most likely make? The student multiplied by 6 instead of 10. The student multiplied by 10 instead of 6. The student used the ratio of 1:4,000 instead of 2:4,000. The student used the ratio of 2:2,000 instead of 1:2,000.

Incomplete question

Step-by-step explanation:

What error did the student most likely make? The student multiplied by 6 instead of 10. The student multiplied by 10 instead of 6. The student used the ratio of 1:4,000 instead of 2:4,000. The student used the ratio of 2:2,000 instead of 1:2,000.

When the student multiply by 6 instead of 10

Let say the value he wanted to mulipty is x

Then the true value is 10x

Then the measure value is 6x

%error= |measure value-true value|/ true value × 100

%error=|6x-10x|/10x ×100

%error= 4x/10x × 100

%error= 40%

When he was suppose to multiply by 6, he then multiply by 10.

Let say the value he wanted to multiply is x

Then the true value is 6x

Then the measure value is 10x

%error= |measure value-true value|/ true value × 100

%error=|10x-6x|/6x ×100

%error= 4x/6x × 100

%error= 66.67%

When the student suppose to do 2:4000, he did 1:4000

The let assume what he want to find it's ration is y

The true value is 2:4000 of y

True value= 2/4000×y

True value =y/2000

Then measure value 1:4000 of y

Measure value = y/4000

%error=|measure value - true value|/ true value × 100

%error= (y/2000-y/4000)/y/2000 ×100

%error= y/4000/y/2000×100

%error= 2000/4000×100

%error= 50%

The student use 2:2000 instead of 1:2000

The let assume what he want to find it's ration is y

The true value is 1:2000 of y

True value= 1/2000×y

True value =y/2000

Then measure value 2:2000 of y

Measure value = 2y/2000

%error=|measure value - true value|/ true value × 100

%error= (2y/2000-y/2000)/y/2000 ×100

%error= y/2000/y/2000×100

%error= 2000/2000×100

%error= 100%

Doubled

it is x equals 3   plese mark me really need it

step-by-step explanation: