Assume that when with smartphones are randomly selected, 46% use them in meetings or classes. If 12 adult smartphone users are randomly selected, find the probability that fewer than 3 of them use their smartphones in meetings or classes.

The probability that fewer than 3 of them use their smartphones in meetings or classes is 0.03634

Step-by-step explanation:

Apply binomial probability formula which is written as;

where P=46% =0.46, n=12

For this case where you find the probability that fewer than 3 of them use their smartphones in meeting or classes, x=2,1,0

Evaluating binomial probability at x=2 will be;

P(X=2)=0.02944

Evaluate binomial probability at x=1

P(X=1)= 0.006284

Evaluate binomial probability at x=0

P(X=0)=0.0006148

Now for P(X<3)=P(X=2)+P(X=1)+P(X=10) =0.02944+0.006284+0.0006148

=0.0363388

=0.03634 (in 4 significant figures)

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this