Suppose that a sequence is defined as follows. This the 1st four terms of the sequence. ASAP BRANLIEST TY!!

- 3, 16, - 22, 54

Step-by-step explanation:

Using the recursive formula with a₁ = - 3, then

a₂ = - 2a₁ + 10 = - 2(- 3) + 10 = 6 + 10 = 16

a₃ = - 2a₂ + 10 = - 2(16) + 10 = - 32 + 10 = - 22

a₄ = - 2a₃ + 10 = - 2(- 22) + 10 = 44 + 10 = 54

Thus

the first 4 terms of the sequence are

- 3, 16, - 22, 54

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)