Find the 9th term of the geometric sequence whose common ratio is ⅔ and whose 1st term is 2. BRANLIEST ASAP TY!!!

512/6561

Step-by-step explanation:

nth term = a×[r^(n-1)]

9th term: n = 9

2×[⅔^(9-1)]

2(⅔^8)

512/6561

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

the answer is 13 cm