Part a) 2,000 mL of solution A
Part b) 40 mL of solution A and 60 mL of solution B
Part c) Is not possible
Step-by-step explanation:
Part a) How many mL of Solution A must be added to 500 mL of Solution B in order to produce a 70% acid solution?
Remember that
![80\%=80/100=0.80](/tpl/images/0520/6702/1d3d6.png)
![30\%=30/100=0.30](/tpl/images/0520/6702/9ad30.png)
![70\%=70/100=0.70](/tpl/images/0520/6702/ecfd8.png)
Let
x ---->mL of solution A n 80% acid solution
y ---->mL of solution B n 30% acid solution
we know that
![0.80x+0.30y=0.70(x+y)](/tpl/images/0520/6702/24343.png)
Remember that
----> equation B
substitute equation B in equation A
![0.80x+0.30(500)=0.70(x+500)](/tpl/images/0520/6702/e4d35.png)
solve for x
![0.80x+150=0.70x+350\\0.10x=200\\x=2,000\ mL](/tpl/images/0520/6702/224db.png)
Part b) How many mL of Solution A and how many mL of Solution B must be combined to form a 100 mL solution that is 50% acid?
Remember that
![80\%=80/100=0.80](/tpl/images/0520/6702/1d3d6.png)
![30\%=30/100=0.30](/tpl/images/0520/6702/9ad30.png)
![50\%=50/100=0.50](/tpl/images/0520/6702/849f6.png)
Let
x ---->mL of solution A n 80% acid solution
y ---->mL of solution B n 30% acid solution
we know that
----> equation A
-----> equation B
Solve the system by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is (40,60)
see the attached figure
therefore
40 mL of solution A and 60 mL of solution B
Part c) Is there a combination of Solution A and Solution B that is 90% acid?
Is not possible , because 90% is greater than 80% of solution A and greater than 30% of solution B
The percentage of the final concentration must be less than 80% and more than 30%
![IF YOU HELP ME I'LL GIVE YOU: EXTRA POINTS BRAINLIEST VOTES AND THANKS Solution A is an 80% acid sol](/tpl/images/0520/6702/56301.jpg)