How do you write the equation in standard form for the circle x² + y² + 2y - 35 = 0

I just don't understand what to do with the "y" values.

So far, I am getting x² + (Somethingnotsurewhat)² = 35

I'm sorry that I am posting the same question again, but I really need some help. (I also can't figure out how to edit).
Please give an explanation for your answer.

Question: Write in standard form.

Step-by-step explanation:

You group all your terms that have a in it together.

You group all your terms that have a in it together.

You put everything that doesn't have a variable on the opposing side.

Let's begin.

Add 35 on both sides:

Group terms together that have a in it and do the same for the terms.

The neat thing here is we don't really need to do anything for the 's since

Whatever we add to one side we must add to the other.

[Side note: You are going to complete the squares for the terms using the following identity:

.

]

So we are going to add on both sides (notice the coefficient of is 2 and the coefficient of is 1).

Applying the right hand side of the identity in my side note:

The cool thing about standard form is that it tells you the center and the radius.

In this case the center is (0,-1) and the radius is 6.

Standard form of a circle is where is the center and is the radius.

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong