Mary jogged from Point P to Point Q while Wyatt jogged from Point Q to Point P.
Point P and point Q are 7.5 kilometers apart.
Mary’s motion is represented by d = 8t and Wyatt’s motion is represented by 2d + 14t = 15, where t hours is the time and d kilometers is the distance from point P. Solve for linear equations. When did Mary and Wyatt meet? minutes later
How far from point Q did they meet? km

When did Mary and Wyatt meet? 0.5 minutes later

How far from point Q did they meet? 3.5 km

Step-by-step explanation:

Mary’s motion is represented by d = 8t----(1)

Wyatt’s motion is represented by 2d + 14t = 15----(2)

We solve for d in equation (2) to get:d=7.5-7t----(3)

We equate equation (1) and (3) to get:

We now solve for t to get:

Now put t=0.5 into equation (1) to get d=0.5*8=4

This means they met 4 km from point P.

Therefore they meet 7.5-4=3.5km from point Q

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)