A football team wins its weekly game with probability 0.7. Suppose the outcomes of games on 3 successive weekends are independent. What is the probability the number of wins exceeds the number of losses

78.8% probability the number of wins exceeds the number of losses.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or they lose. Suppose the outcomes of games on 3 successive weekends are independent. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

In this problem we have that:

What is the probability the number of wins exceeds the number of losses

It is the team winning 2 games, or all three. So

In which

78.8% probability the number of wins exceeds the number of losses.

55% are girls and 45% are boys : ) hope this

step-by-step explanation: