If 2x^2+5x-12=(2x-3)(x+4) which equations should be solved to find the roots of 2x^2+5x-12=0

The equation should be solved to find the roots of 2x² + 5x - 12 = 0 is

(2x - 3)(x + 4) = 0

Step-by-step explanation:

The roots of an equation is values of x when y is equal to zero

∵ y = 2x² + 5x - 12 is a quadratic equation

∴ The roots of the equations are values of x when y = 0

∵ The factorization of 2x² + 5x - 12 is (2x - 3)(x + 4)

∵ 2x² + 5x - 12 = (2x - 3)(x + 4)

∵ 2x² + 5x - 12 = 0

- Equate the right hand side above by 0

∴ (2x - 3)(x + 4) = 0

- Now equate each bracket by 0 to find the values of x

∵ 2x - 3 = 0

- Add 3 to both sides

∴ 2x = 3

- Divide both sides by 2

∴ x = 1.5

∵ x + 4 = 0

- Subtract 4 from both sides

∴ x = -4

∴ The roots of the equations are -4 and 1.5

The equation should be solved to find the roots of 2x² + 5x - 12 = 0 is

(2x - 3)(x + 4) = 0

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

step-by-step explanation:

idk the answer i want to say 10 but then it would be equal so try 9 but then yeah so yeah we love edgen