All that is left in a packet of candy are 5 reds, 2 greens, and 2 blues. (a)What is the probability that a random drawing yields a green followed by a blue assuming that the first candy drawn is put back into the packet?

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Step-by-step explanation:

The candies in the packet are:

r = 5 (number of red candies)

g = 2 (number of green candies)

b = 2 (number of blue candies)

The total number of candies in the packet at the beginning is:

n = r + g + b = 5 + 2 +2 = 9

Therefore, at the first attempt, the probability of drawing a green candy is:

Then, the first candy is placed back in the packet, so still

n = 9

Therefore, at the second attempt, the probability of drawing a blue candy is

Therefore, the probability that a random drawing yields a green followed by a blue is:

isocolese triangle

we know that the line connect a and b is the hyptonuse

so first find the hypotonuse length using the distance formula, call the length c

since it is an isocolese triangle, the lengths of the legs are the same

using pythagorean theorem,

in this case, a=b since isocolese triangle so we get

or

we can find c so we can find the distances

we know that if we draw 2 circles, each has center at a and b, and find where they intersect, we can the 2 possible locations for c

if a has center at (xa,ya) and b has center at (xb,yb), then we can solve where

and

intersect to find where they intersect

i'm not going to put an example because i have to go to class. i hope this explanation is enough