A menu offers a choice of 22 salads, 77 main dishes, and 55 desserts. How many different meals consisting of one salad, one main dish, and one dessert are possible?

70 different meals

Step-by-step explanation:

A menu offers a choice of 2 salads, 7 main dishes, and 5 desserts

There are 3 types of choices are given

each one have different choices. we need to select one salad, one main dish and one dessert

To find the number of different meals we multiply the different choices

so 70 different meals

∞ this is your sign

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b