The math department of a college has 20 faculty members, of whom 5 are women and 15 are men. A curriculum committee of 4 faculty members is to be selected. How many ways are there to select the committee that has more women than men?

155 ways are there to select the committee that has more women than men.

Step-by-step explanation:

The order is not important.

For examle, a committee of John, Elisa, Josh and Rose is the same committee as Elisa, John, Josh and Rose. So we use the combinations formula to solve this problem.

Combinations formula:

is the number of different combinations of x objects from a set of n elements, given by the following formula.

How many ways are there to select the committee that has more women than men?

It can either be 3 women and a men, or 4 women.

3 women and a men

1 men from a set of 15

3 women from a set of 5

4 women

4 women from a set of 5

Total

150 + 5 = 155

155 ways are there to select the committee that has more women than men.

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

sorry, i can't understand your question. will later if you describe more clearly!

: )