If f(x) = 3x 2 + 1 find f(6).

f(6) = 109

Step-by-step explanation:

If f(x) = 3x 2 + 1 we replace x with 6 in the given function

f(6) = 3×6^2 + 1 first find the second power of 6

6^2 = 36 then multiply it by 3

36 × 3 = 108 and then add 1

108 + 1 = 109

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

idc

step-by-step explanation:

idk