He data represents the daily rainfall (in inches) for one month. Construct a frequency distribution beginning with a lower class limit of 0.000.00 and use a class width of 0.200.20. Does the frequency distribution appear to be roughly a normal distribution? 0.450.45 0 0 0 0.210.21 0 0.210.21 0 0.020.02 0.210.21 0.480.48 0 0 0.120.12 0 0.230.23 0 0.480.48 0 1.311.31 0 0 0.230.23 0 0.020.02 0 0.280.28 0 0.180.18 0 Daily Rainfall (in inches) Frequency 0.00 dash 0.190.00-0.19 nothing 0.20 dash 0.390.20-0.39 nothing 0.40 dash 0.590.40-0.59 nothing 0.60 dash 0.790.60-0.79 nothing Daily Rainfall (in inches) Frequency 0.80 dash 0.990.80-0.99 nothing 1.00 dash 1.191.00-1.19 nothing 1.20 dash 1.391.20-1.39 nothing Enter your answer in the edit fields and then click Check Answer.

110

step-by-step explanation:

based on the question i am guessing that it is a typo for abc

if y=4x then you will substitute 4x in for y in the second equation.

8x + 4x = 18 combine like terms

12x = 18 divide by 12 on both sides

x = 18/12 or 3/2

now replace x in the first equation with 3/2 to get

y = 4 3/2

y = 6

the answer is a

(3/2,6)

hope that .

brainliest is always apprectiated

look at the picture.

1.

ef : ab = 2 : 3

gf : cb = 2 : 3

gh : cd = 2 : 3

he : da = 2 : 3

2.

∠a ≅ ∠e

∠b ≅ ∠f

∠c ≅ ∠g

∠d ≅ ∠h

3.

use pythagorean theorem:

the length of the abcd trapezoid sides:

|ab| = 3 cm

|bc| = 10 cm

|cd| = 3(3) cm = 9 cm

|da| = 8 cm

the perimeter of abcd = 3 + 10 + 9 + 8 = 30 cm

the ratio of perimeters of the tarapezoids is equal 2 : 3.

substitute:

      cross multiply

      divide both sides by 3