BusinessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message user receive or send per hour? (2 pts) What is the probability that a text message user receives or sends three messages per hour? (3 pts) What is the probability that a text message user receives or sends more than three messages per hour? (3 pts)

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let X = number of text messages receive or send in an hour.

The random variable X follows a Poisson distribution with parameter λ.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: .

The probability of a random variable can be computed using the formula:

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

45

step-by-step explanation:

to find a percentage, add a decimal in front and multiply it by the other number.

.25 times 180= 45

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.