Peter the optician sees 16 patients one Tuesday.4 are neither short nor long sighted, the total number of short sighted patients is 2 more than the total number of long sighted, how many patients can be short sighted, how many long sighted, and how many will require varifocal lenses

The number of short-sighted patients is 7

The number of long-sighted patients is 5

The number of patients requiring a varifocal lens is 4

Step-by-step explanation:

Stepwise solution-

Throughout the question, only 3 types of patients are mentioned. Hence, it would be safe to assume that he saw/sees these 3 types of patients on Tuesday.

As per the given details-

4 are neither short-sighted patients nor long-sighted patients. Then it means no of varifocal lens patients is 4.

Hence remaining total patients=16-4=12

As given, no of short-sighted patients is 2 more than the number of long-sighted patients.

Let us assume the number of long-sighted patients as “x”

Thus, the number of short-sighted patients would be “x+2”

x+(x+2)=12   (total remaining patients)

2x=10

x=5

Hence, No. of long-sighted outpatients = 5

            No. of short-sighted outpatients =7

(x+3)(x+7)

step-by-step explanation: