Find parametric equations for the tangent line to the given curve at the point(213252656). The curve and the tangent line must have the same velocity vector at this point.

x(t)=1+4ty(t)=3t32?2tz(t)=4t2+6t+6
x(t)=
y(t)=
z(t)=
Give the unit tangent vector to the curve at (213252656)
T=