Consider the parabola r(t)equalsleft angle at squared plus 1 comma t right angle, for minusinfinityless thantless thaninfinity, where a is a positive real number. Find all points on the parabola at which r and Bold r prime are orthogonal?

t=0

Step-by-step explanation:

r=<+1,>

by differentiating the r vector component by component

r' = <2at, 1>

Two vector are orthogonal when the dot product between them is zero, so:

r'·r=0

<+1,>·<2at, 1>=2+2at+t=0

common factor

t(+2a+1)=0

Then, the only real value for t is zero.

-> t=0

16.9 times 2.85

step-by-step explanation:

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: