At time t, the position of a body moving along the s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m. a. Find the body's acceleration each time the velocity is zero. b. Find the body's speed each time the acceleration is zero. c. Find the total distance traveled by the body from tequals0 to tequals5.

Step-by-step explanation:

Given that at time t, the position of a body moving along the s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m

i.e.

Velocity is nothing but s'(t) = derivative of s

and acceleration is s"(t) = derivative of v(t)

a) v(t) =0 when t = 4 or 6

b)

a(t) =0 when t =5

c) Distance travelled by the body from 0 to 5 would be

i.e. 110 miles (distance cannot be negative)

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9