Find an equation of the line satisfying the conditions. Write the equation in slope-intercept form. Through (-6,7); parallel to 3x+7y=3

solve 3x+7y=3 (rearrange to y=mx+c)

7y = -3x+3

parallel line to this...it goes through (-6,7)

so y=(-3/7)x+c - same slope, since it's parallel

when x is -6, y is 7 (-6,7)

so...

7=(-3/7)*-6+c

7= 2.571428571428571428571428571428...+c

c= 4.428571429

then we get the equation...

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.