Find the value of x and y in these equation.
(a^x*b^y)^(1/6)=a^(1/2)*b^-(1/3)

x=3 y=-2

Step-by-step explanation:

you must take the right part of the equation and express it as (something)^1/6

you know that the general formula is (a^b)^c = a^(b*c)

and (ab)^c = (a^c)*(b^c)

so you must reach a situation where you express everything ^1/6

a^(1/2) = a^(3/6) = (a^3)^1/6

b^(-1/3) = b^(-2/6)=(b^-2)^1/6

AND

((a^3)^1/6)*((b^-2)^1/6) = (a^3*b^-2)^1/6

therefore

x=3 and y=-2

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step-by-step explanation:

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y