What is the equation of the line that is parallel to the given line and passes through the point (-2, 2)?

5y = x +12

Divide through by 5 to obtain the slope_intercept form as

y=x/5 + 12/5

Step-by-step explanation:

From the given graph, slope of the line is

y2-y1/x2-x1 = -3-(-4)/0-(-5) = -3+4/0+5 = 1/5

Slope, m1 of the given line is 1/5

Therefore, m2 of the unknown line is the same 1/5 because it's parallel to the given line

hence

The equation passing through (-2,2) and parallel to the known line is

y-y1 = m2(x-x1)

y-2 = 1/5(x-(-2))

y-2 = 1/5(x+2)

y = x/5 + 2/5 +2

Multiply through by 5

5y = x +2+10

5y = x +12

Divide through by 5 to obtain the slope_intercept form as

y=x/5 + 12/5

(3x-8) or (3x+8)

step-by-step explanation: