Write the general equation for the circle that passes through the points (- 5, 0), (0, 4), and (2, 4).
You must include the appropriate sign (+ or -) in your answer. Do not use spaces in your answer.
4x² + 4y² ___x ___y ___ = 0

[tex]4x^2+4y^2+72x-81y+260=0

Step-by-step explanation:

For the point (-5,0) we have

4*(-5)^2+4*0^2+a*(-5)+b*0+c=0

100-5a+c=0

-5a+c=-100.......(1)

Fro the point (0,4) we have:

4*0^2+4*4^2+a*0+b*4+c=0

64+4b+c=0

4b+c=-64.....(2)

For the point (2,4) we have:

4*4+4*16+2a+4b+c=0

16+64+2a+4b+c=0

2a+4b+c=80.....(3)

(3)-(2):

2a+4b+c-4b-c=80+64

2a=144

a=72

So we have:

-5*72+c=-100

c=260

And from (2) we have

4b+260=-64

b=-81

false

step-by-step explanation:

rulers and compasses arent required in order to bisect an angle because when bisecting angles, you're making a "half circle" and considering in order to bisect an angle it wouldn't be straight, you wouldn't need either of the two

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1