![2x^2y[x^{2}y^{2}-6xy-4]](/tpl/images/0523/7099/45c4c.png)
Factor completely 2x4y3 − 12x3y2 − 8x2y.
2x2y(x2y2 − 6xy − 4)
2(x4y3 − 6x3y2 − 4x2...
Mathematics, 25.02.2020 21:23 nik2lit
Factor completely 2x4y3 − 12x3y2 − 8x2y.
2x2y(x2y2 − 6xy − 4)
2(x4y3 − 6x3y2 − 4x2y)
2y(x4y2 − 6x3y − 4x2)
Prime
Answers: 1
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