In 2016 a population of deer in an area was estimated to be 500 with a growth rate of 8% each year. Which of the following models the estimated population of deer in “t” years?

A. P(t)=500(1.08)^t
B. P(t)=500(1.8)^t
C. P(t)=500(0.08)^t
D. P(f)=500(0.82)^t

Step-by-step explanation:

The growth rate is exponential. We would apply the formula for exponential growth which is expressed as

A = P(1 + r)^t

Where

A represents the population of the deer after t years.

t represents the number of years.

P represents the initial population of the deer.

r represents rate of growth.

From the information given,

P = 500

r = 8% = 8/100 = 0.08

Therefore, the models that estimates the population of deer in “t” years is

A. P(t)=500(1.08)^t

10.416 meters per second

step-by-step explanation:

distance=1 00 meters

time= 9.6 seconds in decimal form or 9 3/5 as a mixed number

average speed= 100/9.6

=10.416 meters per second or 10 52/125 as a mixed number.

answer: 80,000

step-by-step explanation:

the population doubles every day.

10,000*2=20,000 day 4

20,000*2=40,000 day 5

40,000*2=80,000 day 6