Mathematics, 26.02.2020 02:47 Abdimshsiwnsbs9686
Verify that y1(t) = 1 and y2(t) = t1/2 are solutions of the differential equation yy + ( y)2 = 0 for t > 0. Then show that y = c1 + c2t1/2 is not, in general, a solution of this equation. Explain why this result does not contradict Theorem 3.2.2.
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Verify that y1(t) = 1 and y2(t) = t1/2 are solutions of the differential equation yy + ( y)2 = 0 for...
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