Suppose that distinct integer values are written on each of 3 cards. These cards are then randomly given the designations A, B, and C. The values on cards A and B are then compared.
1. If the smaller of these values is then compared with the value on card C, what is the probability that it is also smaller than the value on card C?

2/3

Step-by-step explanation:

The possible outcome from the three designations is express as 3!

and 3!=3x2x1=6

Hence the 6 possible outcome are listed below

(A,B,C),(A,C,B),(B,A,C),(B,C,A),(C,A,B) and (C,B,A)

let assume A should be less than B and B less than C, i.e A<B<C

The question required us to solve for

P(min(A,B)<C). And this can be expressed as

P(min(A,B)<C)=P(A<C)+P(B<C)-P(AB<C).

From the order given above, there are 3 possible outcome for A to come before C

Hence P(A<C)=3/6=1/2

also there 3 possible outcome for B to come first before C

P(B<C)=3/6=1/2

Also, there 2 events for A,B to come before C

P(AB<C)=2/6=1/3

Hence in final

P(min(A,B)<C)=P(A<C)+P(B<C)-P(AB<C)=1/2+1/2-1/3=2/3

the probability that it is also smaller than the value on card C is 2/3

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

answer

false

explanation

these practices describe the manner the land use outcome is attained. land management methods implemented by corporations are a mandatory because they are a driver for better land use results economically, socially and environmentally. corporations are required to understand the connection between land use , and land management practices to support sustainable land use policies