Assume that a TCP sending sliding window is of size 6 and currently includes bytes 4, 5, 6, 7, 8, and 9. The next byte to be sent is byte 4. Show the sender sliding window (only) and state what sequence number (if any) will be sent after each step in the following sequence of events.

TCP is byte stream protocol because every data byte that are sent are counted. In TCP every byte is given a specific number based on their sequence. Sequence number of any segment is nothing but the number given to first byte in segment. Acknowledge number is always the next byte number that receiver expects the sender to send next.

a). initial condition window : 4,5,6,7,8,9  

b).Sends a segments with 3 bytes window: 7,8,9,10,11,12

Step-by-step explanation:

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.