A company is considering two different campaigns, A and B, for the promotion of their product. Two tests are conducted in two market areas with identical consumer characteristics, and in a random sample of 60 customers who saw campaign A, 18 tried the product. In a random sample of 100 customers who saw campaign B, 22 tried the product. What conclusion can management reach?

There is no sufficient evidence of a difference in the effectiveness of the two ad campaigns.  

Step-by-step explanation:

We are given the following in the question:

Let p1 and p2 be the proportion from campaign A and B, respectively, that are defective.

First, we design the null and the alternate hypothesis

We use Two-tailed z test to perform this hypothesis.

Formula:

Putting all the values, we get,

Now, we calculate the p-value from the table at 0.05 significance level.

P-value = 0.25789

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept it.

Conclusion:

Thus, we conclude that there is no sufficient evidence of a difference in the effectiveness of the two ad campaigns.

step-by-step explanation:

answer: the common difference is -0.10