Let f={(-2,4),(-1,2)(0,0)(1,-2),(2,5)}. let g ={(-33),(-1,1),(0,-3)(1,-4)(3,-6)}. What is g(f(2))?

g(f(2)) does not exist if

g={(-3,3),(-1,1),(0,-3),(1,-4),(3,-6)} and f={(-2,4),(-1,2),(0,0),(1,-2),(2,5)}.

Step-by-step explanation:

Hi. Welcome to .

When finding g(f(2)), you must compute f(2) first.

Looking at f={(-2,4),(-1,2),(0,0),(1,-2),(2,5)}, we see that the ordered pair (2,5) is contained within the set defined as the set f. This means f(2)=5.

So now we have g(f(2))=g(5).

We now need to look at our set named g, g={(-3,3),(-1,1),(0,-3),(1,-4),(3,-6)}. We see the the no ordered pair looks like (5,something). The only conclusion is that g(f(2)) does not exist.

no problobm

step-by-step explanation:

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1