Beatrice participates in professional triathlons. She runs 2 mph faster than her friend Joe, a weekend athlete. If they each
run 12 mi, Beatrice finishes 30 min ahead of Joe. Determine how fast each person runs.

Speed of  Joe is 6  mph and that of  Beatrice  is 8 mph

Step-by-step explanation:

Let Joe's speed be S

Beatrice's speed be s + 2

Let  Joe's time be  T

Beatrice's time = T - 1/2

Then

We know that

Now

Distance  =

On substituting the value

Equation corresponding to Joe

...........................(1)

 Equation corresponding to Beatrice

Now solving for s and T,we get

S = 6 mph -------------------------- Joe's speed

T = 2 hours ------------------------ Joe's time

Thus Beatrice's speed  is

6 + 2 = 8 mph

Beatrice's time is

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

answer: i believe the answer is e

step-by-step explanation: