If a=b^x, b=c^y and c= a^z prove that xyz

=1

If ax=b and by=c, substituting you get that axy=c. Now, if cz=a, substituting again, axyz=a, from where it follows that xyz=1.

or

c = {b^y} = [(a^x)^y] = {a^(xy)}

a = [c^z] = [{a^(xy)}^z] = [a^(xyz)]

(a^1) = [a^(xyz)]

Therefore, (xyz) = 1.

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

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