A group of health care providers consists of 4 doctors, 3 dentists, and 5 nurses. How many combinations of 2 health care providers of different types are possible?

The number of combinations of 2 health care providers of different types possible are 47.

Explanation:

Doctors = 4

Dentists = 3

Nurses = 5

combinations of two different health care providers = ?

Combination would be = ⁴C₁ X ³C₁ + ³C₁ X ⁵C₁ + ⁴C₁ X ⁵C₁

ⁿCₐ = n! / ( n - a )!  X a!

So on calculating the combination we get,

= 4 X 3 + 3 X 5 + 4 X 5

= 12 + 15 + 20

= 47

Therefore, the number of combinations of 2 health care providers of different types possible are 47.

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%