Mathematics, 26.02.2020 16:59 Jasminelane6478

A commuter railway has 800 passengers a day and charges each one 2 dollars. ?
For each 10 cents the fair is increased, 2 fewer people will ride the train. Express the income I from the train in terms of the ticket price p (in dollars). T/F

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Answer from: ash011519

The income I from the train in terms of the ticket price p (in dollars) is;

I = $(-20p² + 840p)

Number of passengers a day = 800 passengers

Charge for each passenger = $2

We are told that for each $0.1 there is an increase in ticket price and the number of passengers will be 2 fewer people.

Thus;

Number of passengers is now (800 - 2x)

The ticket price is now; p = $(2 + 0.1x)

Thus;

Let us make x the subject of the formula from the price equation to get;

x = (p - 2)/0.1

x = 10p - 20

Putting 10p - 20 for x in (800 - 2x) gives;

Number of passengers = 800- 2(10p- 20)

Number of passengers = 800 - 20p + 40

Number of passengers = 840- 20p

Income is calculated by multiplying the number of the passenger by the ticket price. Thus, if income is denoted by I, then;

I = p(840 - 20p)

I = -20p² + 840p

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A commuter railway has 800 passengers a day and charges each one 2 dollars. ?
For each 10 cent...

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