Use the following scenario for all questions. The marketing manager of a grocery store observed customers going to the baby’s section. She found that 62% of all customers buy buby formula, 52% of all the customers buy diapers and 38% of all customers buy both baby formula and diapers. Use B to denote the event that a randomly selected customer buys baby formula and D to denote the event that a randomly selected customer buys diaper. Thus the information given above can be written as P(B)=0.62, P(D)=0.52 and P(B∩D)=0.38. What is the probability that a randomly selected customer buys either baby formula or diaper?

76% probability that a randomly selected customer buys either baby formula or diaper

Step-by-step explanation

We solve this problem building the Venn's diagram of these probabilities.

There are two events, events B and D.

We have that:

In which P(b) is the probability of only b and is the probability of both B and D.

By the same logic, we have that:

P(B)=0.62, P(D)=0.52 and P(B∩D)=0.38.

So

And

What is the probability that a randomly selected customer buys either baby formula or diaper?

76% probability that a randomly selected customer buys either baby formula or diaper

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3