A ball is thrown straight upward. At 4.00 m above its launch point, the ball’s speed is one-half its launch speed. What maximum height above its launch point does the ball attain?

Step-by-step explanation:

Conservation of the Energy

The total mechanical energy of an object is conserved if no external forces (like friction) are applied. When the ball is thrown upwards, the gravitatory potential energy is 0 because its height is also 0. But the kinetic energy is at max because the speed is at its maximum value. Let's assume vo is the initial speed and H is the maximum height the ball will eventually reach. The initial kinetic energy is totally converted to gravitational potential energy when the ball reaches its maximum height and the speed is zero, thus

Solving for H

To find vo, we use the given condition: at h=4 m above the launch point the speed is one-half the launch speed. Thus the total energy at that moment is

Operating

This total energy is equal to the initial kinetic energy:

Simplifying by m and multiplying by 8

Solving for vo

Finally, replacing in the equation for H

angle uzt is congruent to angle tzy. angle vzw is congruent to angle yzx.

(credits to leowren)

step-by-step explanation:

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step-by-step explanation:

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